Discriminant of a number field
Annoying index
Given a number field
the annoying index,1 alg
since it measures the degree to which
Properties
- If
is squarefree, thenΞ πΎ : β ( πΌ 1 , β¦ , πΌ π ) is an integral basis.{ πΌ π } π π = 1 - If the minimal polynomial
forπ πΌ ( π₯ ) is Eisenstein atπΌ β O πΎ , thenπ does not divideπ .| O πΎ / β€ [ πΌ ] |
Proof
^P1 follows immediately from ^EQ1.
For ^P2, suppose towards contradiction that
divides the annoying index. Then by Cauchyβs order theorem there exists π such that π β O πΎ has order π + β€ [ πΌ ] , i.e. π and π β β€ [ πΌ ] . It follows we can write π π β β€ [ πΌ ] π π = π β 1 β π = 0 π π πΌ π for some
where some π π β β€ is not divisible by π π . Fix π to be the smallest such index. It follows π π = π β π β 1 β π = 0 π π π πΌ π = π β 1 β π = π π π π πΌ π β O πΎ . and so
π πΌ π β π β 1 = π π π πΌ π β 1 + πΌ π π π β π β 2 β π = 0 π π + π + 1 πΌ π β O πΎ . Since
πΌ π π = β π β 1 β π = 0 π π π πΌ π β O πΎ it follows
, so the field norm π½ = π π π πΌ π β 1 β O πΎ . N πΎ : β β‘ ( π½ ) β β€ On the other hand
N πΎ : β β‘ ( π½ ) = π π π π π N πΎ : β β‘ ( πΌ ) π β 1 = Β± π π π π π β 1 0 π π β β€ since
and π β€ π π , a contradiction. π 2 β€ π 0
Footnotes
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This term is taken from lectures by Florian Breuer and should not be taken too seriously. β©