Canonical projections are open
Let
Proof
Denote with
the topology of T πΌ . Consider the subbasis π πΌ of A π = { π β 1 πΌ π : π β T πΌ : πΌ β π΄ } , and let π be a subbasic open set. Then π β A π for some π = π β 1 πΌ ( π ) , and since π β T πΌ is surjective, π πΌ . Hence π πΌ ( π β 1 πΌ ( π ) ) = π = π πΌ ( π ) is open. Thus, by Proving open map with a subbasis, each π πΌ ( π ) is an open map. π πΌ