Formal sums over a vector space

Degree operator on formal sums over a vector space

Let 𝑉 be a vector space over 𝕂 and 𝑉{𝑧} denote formal sums over 𝑉. We define the 𝑧-degree operator1 fcalc

𝐷=𝐷𝑧=𝑧𝑑𝑑𝑧,

where 𝑑𝑑𝑧 is the Formal derivative. This is not strictly a degree operator, as 𝑉{𝑧} is not a graded vector space, however its subspaces 𝑉[𝑧] and 𝑉[𝑧,π‘§βˆ’1] are.

Properties

Over a graded vector space

Now taking 𝑉 to be 𝕂-graded with degree operator 𝑑 ∈End⁑𝑉, and letting

𝑣(𝑧)=βˆ‘π‘›βˆˆπ•‚π‘£π‘›π‘§π‘›βˆˆπ‘‰{𝑧}𝑋(𝑧)=βˆ‘π‘›βˆˆπ•‚π‘₯(𝑛)π‘§βˆ’π‘›βˆˆ(End⁑𝑉){𝑧}

we have

𝐷𝑣(𝑧)=𝑑𝑣(𝑧)⟺(βˆ€π‘›βˆˆπ•‚)[deg⁑𝑣𝑛=𝑛]βˆ’π·π‘‹(𝑧)=[𝑑,𝑋(𝑧)]⟺(βˆ€π‘›βˆˆπ•‚)[deg⁑π‘₯(𝑛)=𝑛]

With the formal Dirac delta

Let 𝛿(𝑧) βˆˆπ•‚[[𝑧,π‘§βˆ’1]] denote the Formal delta. Then it follows from Properties that for any 𝑣(𝑧) βˆˆπ‘£[𝑧,π‘§βˆ’1] and π‘Ž βˆˆπ•‚Γ—

𝑣(𝑧)𝐷𝛿(π‘Žπ‘§)=𝑣(π‘Žβˆ’1)𝐷𝛿(π‘Žπ‘§)βˆ’(𝐷𝑣)(π‘Žβˆ’1)𝛿(π‘Žπ‘§)

and that for any 𝑋(𝑧1,𝑧2) ∈(End⁑𝑉)[[𝑧1,π‘§βˆ’11,𝑧2,π‘§βˆ’12]] such that lim𝑧1→𝑧2𝑋(𝑧1,𝑧2) exists and π‘Ž βˆˆπ•‚Γ—

𝑋(𝑧1,𝑧2)𝐷1𝛿(π‘Žπ‘§1/𝑧2)=𝑋(π‘Žβˆ’1𝑧2,𝑧2)𝐷1𝛿(π‘Žπ‘§1/𝑧2)βˆ’(𝐷1𝑋)(π‘Žβˆ’1𝑧2,𝑧2)𝛿(π‘Žπ‘§1/𝑧2)𝑋(𝑧1,𝑧2)𝐷2𝛿(π‘Žπ‘§1/𝑧2)=𝑋(𝑧1,π‘Žπ‘§1)𝐷2𝛿(π‘Žπ‘§1/𝑧2)βˆ’(𝐷2𝑋)(𝑧1,π‘Žπ‘§1)𝛿(π‘Žπ‘§1/𝑧2)

where 𝐷1 =𝐷𝑧1 and 𝐷2 =𝐷𝑧2.


tidy | en | SemBr

Footnotes

  1. 1988. Vertex operator algebras and the Monster, pp. 56–58 ↩