Krull dimension of an integral domain
Let
Proof
^C1. So if
is a field, . Conversely, if then is a maximal ideal (as Every commutative ring has a maximal ideal and A maximal ideal in a commutative ring is prime), and thus has no nonzero proper ideals: is a field. Note for
every nonzero prime ideal is maximal by vacuity. Given , then any nonzero prime ideal is contained within a maximal ideal which is also prime (since Every ideal in a commutative ring is contained in a maximal ideal), but this must be equal to or else implies .
Footnotes
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2022. Algebraic number theory course notes, ¶1.23, p. 15 ↩