Lower bound on the dimension of the field of rational functions
Let
In particular, the following set linearly independent:
Proof
Let
π π ( π₯ ) = π π ( π₯ ) π π ( π₯ ) = π β π = 1 1 π₯ β π π where
π π ( π₯ ) = π β π = 1 ( π₯ β π π ) then
π π + 1 ( π₯ ) = π π ( π₯ ) π π ( π₯ ) + 1 π₯ β π π + 1 = π π ( π₯ ) ( π₯ β π π + 1 ) + π π ( π₯ ) π π ( π₯ ) ( π₯ β π π + 1 ) which is zero iff
. But this is impossible since π π ( π₯ ) = β ( π₯ β π π + 1 ) π π ( π₯ ) . ( π₯ β π π + 1 ) β€ π π ( π₯ )