Noetherian ring
A ring
- every (left) ideal
is finitely generated as a (left)๐ผ โด ๐ -module, i.e.๐ is a (left) Noetherian module;๐ - (ascending chain condition or ACC) every increasing sequence
of (left) ideals of๐ผ 1 โด ๐ผ 2 โด โฏ has a largest element;๐ - every non-empty set of (left) ideals of
contains a maximal element.๐
Proof
Suppose ^N1 holds, and let
be an increasing sequence of (left/right) ideals. Then ๐ผ 1 โด ๐ผ 2 โด โฏ ๐ผ = โ โ ๐ = 1 ๐ผ ๐ is an ideal, since if
then ๐ฅ โ ๐ผ for some ๐ฅ โ ๐ผ ๐ and thus ๐ resp. ๐ ๐ฅ โ ๐ผ ๐ for any ๐ฅ ๐ โ ๐ผ ๐ . Hence ๐ โ ๐ is finitely generated, and all these generators must be exhausted by some ๐ผ , implying ^N2. ๐ผ ๐ Suppose ^N2 holds, and assume towards contradiction there exists a set
of (left/right) ideals with no maximal element. One can then form a strictly increasing sequence of โ , contradicting ^N2. Therefore ^N2 implies ^N3. ๐ผ ๐ โ โ Suppose ^N3 holds, and let
be an arbitrary (left/right) ideal. Letting ๐ผ โด ๐ be the set of finitely generated ideals contained in โ , which is inhabited since ๐ผ , and thus contains a maximal element 0 โ โ . Assume towards contradiction ๐ผ โฒ โ โ . Then we can take ๐ผ โฒ โ ๐ผ , and form ๐ฅ โ ๐ผ โ ๐ผ โฒ resp. ๐ผ + ๐ ๐ฅ , which is a finitely generated (left/right) ideal strictly larger than ๐ผ + ๐ฅ ๐ , contradicting maximality. Therefore ๐ผ โฒ and ๐ผ โฒ = ๐ผ is finitely generated, so ^N3 implies ^N1. ๐ผ
Properties
Let
- Let
be a nonzero proper ideal. Then there exist nonzero prime ideals๐ผ โ ๐ such that๐ญ 1 , โฆ , ๐ญ ๐ โ ๐ .๐ญ 1 โฏ ๐ญ ๐ โ ๐ผ
Proof
Let
be the set of all ideals for which ^P1 fails, and assume towards contradiction its maximal element is I , which cannot be a prime ideal, so there exist ๐ผ โ I such that ๐ , ๐ โ ๐ โ ๐ผ . Let ๐ ๐ โ ๐ผ and ๐ = ( ๐ผ , ๐ ) , whence ๐ = ( ๐ผ , ๐ ) , so by maximality ๐ผ โ ๐ , ๐ and thus there exist nonzero prime ideals ๐ , ๐ โ I such that ๐ญ 1 , โฆ , ๐ญ ๐ , ๐ฎ 1 , โฆ ๐ฎ ๐ โ ๐ ๐ โ ( ๐ญ 1 โฏ ๐ญ ๐ ) , ๐ โ ( ๐ฎ 1 โฏ ๐ฎ ๐ ) . Then
( ๐ ๐ ) = ( ๐ผ 2 , ๐ ๐ผ , ๐ ๐ผ , ๐ ๐ ) โ ๐ผ whence
( ๐ญ 1 โฏ ๐ญ ๐ ๐ฎ 1 โฏ ๐ฎ ๐ ) โ ๐ผ , a contradiction. Therefore
. I = โ
Other results
- Finitely generated modules over a noetherian ring are noetherian (^P2)
Footnotes
-
2022. Algebraic number theory course notes, ยง2.5, pp. 14โ15 โฉ