Normal quadratic subspace
Let
Away from 2 a subspace is normal iff it is radical
Clearly a normal subspace must be radical. Let
. Then π β€ r a d β‘ π is totally isotropic, since for any π we have π’ β π π ( π’ ) = 1 2 π π ( π’ , π’ ) = 0
Normal subspaces of
Footnotes
-
This terminology is nonstandard, but nice. As Jeff Saunders remarks, it is not only reminiscent of Normal subgroup, but also the fact that such a subspace is βnormalβ to everything else, under the bilinear form. β©