Group theory MOC Normalizer in a group Let πΊ be a group and π βπΊ be a subset. An element π βπΊ normalizes π iff it leaves π invariant under conjugation, i.e. πππβ1=π The normalizer NπΊβ‘(π) of π in πΊ is the subgroup of all elements normalizing π, group i.e. NπΊβ‘(π)={πβπ:πππβ1=π} Proof of subgroup This is just the setwise stabilizer of π under the conjugation action. See also Normalizer in a Lie algebra tidy | en | SemBr