Orthonormal dense basis
Let
Main theorem
If
is an orthonormal dense basis ofE π E β = { 0 } for all| π₯ β© = β β π = 1 | π π β© β¨ π π | π₯ β© π₯ β π
Proof
Assume
is an orthonormal dense basis of E and let π . Note that π = s p a n β‘ E by ^S6. Let E β = π β . Now by the density of π₯ β π β there exists a sequence π in ( | π¦ π β© ) β π = 1 such that π . But since the inner product is continuous l i m π β β | π¦ π β© = π₯ β¨ π₯ | π₯ β© = l i m π β β β¨ π₯ | π¦ π β© = 0 whence $\Span so ^O1 implies ^O2.
Now assume
. Let E β = { 0 } | π₯ π β© = π β π = 1 | π π β© β¨ π π | π₯ β© We will show that
. l i m π β β | π₯ π β© = | π₯ β©
Properties
- Parsevalβs relation allows the expansion of arbitrary inner products.
Footnotes
-
This is nonstandard terminology. Normally, this is just called an orthonormal basis, while the normal definition of a basis is relegated to Hammel basis. β©