Let denote the set of nonconstant monic polynomials in , and let be the corresponding polynomial ring, potentially in infinitely many indeterminates.
Consider the ideal
which we will show must be proper.
Suppose towards contradiction that , so
for some and .
We can then construct an extension where the polynomials have roots , by iteratively Adjoining a root to a field.
If we evaluate
where by construction every nonconstant monic (and thus nonconstant general) polynomial has a root .
To guarantee the existence of all roots we iterate this process ad infinitum,
so not only does have a root ,
but has a root , &c.
This yields a chain of extensions
Let be the union or limit of this chain.
is an algebraically closed field, and [[Algebraic interior of a field extension#^p1|thus is an algebraic closure of ]].
Proof
For every we have for some ,
so we can just work within whatever is necessary, since the result is independent.
Thus is a field.
If , then for some ,
and thus it has a root in .