Galois field
A Galois field is a field containing a finite number of elements. ring
The cardinality of a field is called its order,
and finite fields only exist for orders of the form
Construction and uniqueness
Let
Proof
Let
be the splitting field of over , and be the set of roots of . Since the formal derivative , we have , and thus is a separable polynomial of order , so . We show is a field, whence , since by definition is generated by over . To this end, let
, whence and , so using the Freshman’s dream If
, proving
is closed under subtraction and division, thus it indeed a subfield by the Tests for subfields. For the converse, let
be a field such that . Then , so the multiplicative order of every element is a divisor of . Therefore and we already have
. Thus, has roots in , whence it is the splitting field, as stated.
Direct construction as quotient by a polynomial
A finite field of a given order can be constructed as a quotient of a polynomial ring. Given a polynomial ring
and an irreducible polynomial of degree , then is a field of order . ring
Properties
Let
is a perfect field, and consequently, irreducible polynomials in are separable.
Proof of 1
Since the Frobenius endomorphism is injective (Field homomorphisms are injective), by the Pigeonhole principle it must also be surjective, proving ^P1.
Other results
- Finite extension of a Galois field
- By Wedderburn’s little theorem these are the only finite division rings.
Footnotes
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2009. Algebra: Chapter 0, §VII.5.1, p. 441. ↩