Lattice subgroup
A lattice
Classical lattice
A classical lattice
Let
is a complete lattice subgroup of ; is generated by elements; in .
Proof
Suppose
is discrete. Then
is closed. For if is an isolating neighbourhood of 0, then is an open neighbourhood of
such that and the difference of any elements of lies in . If there were an such that , then there would be a two distinct elements such that , so is not isolated in , a contradiction. Now let
be a -basis of , and let . We will show that the Lagrange index is finite. Let for be a complete system of representatives for each coset. Letting (this is an abuse of notation but the meaning is clear) we have
where
lie discretely in the bounded set
. Since is compact and discrete, and thus finite, it follows is finite, so the are finite and thus is finite. It follows
, whence implying
possesses a -basis of length less than .
See also
- Not to be confused with Lattice order
Footnotes
-
1999. Algebraic number theory, ¶I.4.2, p. 25 ↩