The completion of a metric space may be thought of as the smallest possible metric space containing but with all limits added, anal i.e. a complete metric space.
This notion is made rigorous by the universal property, which ensures uniqueness up to unique isomorphism.
is complete.
If is a complete metric space and such that is dense in ,
then there exists a unique isometry such that ,
i.e. the following diagram commutes
Let denote the set of all Cauchy sequences on ,
For any sequences ,
let
which defines an equivalence relation.
The completion is the quotient
with a metric given by
and .
Validity of construction
First we will show that indeed defines an equivalence relation.
^E1 and ^E2 are clear,
and ^E3 follows from ^M2:
If and ,
then
so .
Next we show that the metric on is well-defined.
Let and .
Then by the ^M2
but by symmetry the reverse inequality holds too,
so .
^M1 and ^M3 follow immediately.
For ^M3 note
as required.
Now we need to show that the given construction is indeed complete.
We make the following observations
Let . If , then so too is every subsequence .
Let .
Since is Cauchy, for every there exists a subsequence such that for all .
Let be a Cauchy sequence in .
For each ,
we fix a representative in such that for all we have .
Since is Cauchy,
for every
there exists an
such that for all
we have
(using that sufficiently large have ).
Now let which is Cauchy in ,
since
for any if and thus we have
We claim is the limit of .
Let and . Then
so .
It remains to show that satisfies the universal property.
Let be a complete metric space and .