No group is the union of two proper subgroups
For any group
Proof
Let
be strict subgroups of such that . Clearly these subgroups cannot be identical, so without loss of generality assume that there exists some such that . For any it follows that . If then which is a contradiction. If then . Therefore for any also , hence and , contradicting the requirement that . Thus no group is the union of two proper subgroups.
For more than two proper subgroups it is possible.
For example, consider the group