Number of points in a finite projective plane
If in an abstract projective plane
- every line of
is incident with points; - every point of
is incident with lines; and contains points and the same number of lines.1
By duality, the same holds if there is a point incident with
Proof
Let the points incident with
be . If then by ^P1 there exist pairwise distinct lines . Now this must exhaust all lines passing through , since each such line must intersect by ^P2 at a point. By duality, if there is a point incident with lines, then every line not through is incident with points. If
is a line distinct from then there exists by ^P4 a third line through , and by ^P3 this is incident with a point . Since , there are lines passing through , and since this yields points on . This proves ^C1, and similarly one shows ^C2. Consider an arbitrary point
, and the lines incident with it. Each of these contains points distinct from each other and , so the total number of points is . By duality, the same holds for lines.
Footnotes
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2020, Finite geometries, p. 6 ↩