Orthogonality by a quadric
Let
be the corresponding bilinear form.1
Then for
- Let
be an arbitrary point. Then iff the line is a secant of , i.e. . - Let
. Then iff the line is a tangent of at , i.e. . - Let
. Then iff the line is a line of , i.e. completely contained in .
Proof
Footnotes
-
2020. Finite geometries, ¶4.50, pp. 104–105 ↩