Projective module
An
This is equivalent to any of the following1
preserves epimorphisms; - Any Module epimorphism
splits; is a direct summand of a free module, i.e. for some module and some cardinal ; is exact.
Proof
If ^P1 holds, then taking
and gives ^P2. If ^P2 holds, consider an epimorphism
. Then the split short exact sequence guarantees the required direct sum decomposition, giving ^P3.
Note that
is already exact if , so since it follows from ^P1 that ^P3 implies ^P4.
Noting that being a module epimorphism is the same as being a regular epimorphism, and that the latter must be preserved by exact functors, it is clear that ^P4 implies ^P3.
Footnotes
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2011. Introduction to representation theory, §8.1, pp. 205–332 ↩