Quadratic integers
The quadratic integers within a quadratic field
Proof
Let
Clearly an element of of degree 1 is an algebraic integer iff it is an integer. Let be a degree 2 element. Then the minimal polynomial of is By ^P1, we have
iff , which is precisely the case when . It follows , so since is squarefree . Letting , , we have iff and . Since is squarefree it follows , so we need only consider the cases
- If
then which holds iff ; - If
then which holds iff ; - If
then which holds iff . It follows that the general expression for an algebraic integer
is
if if where
, whence the above.
In general, a quadratic integer is the solution to some monic quadratic with integer coëfficients.
Properties
Let
- The discriminant is
. - It follows that
Proof of 1
Prime ideals
Let
- If
then is unramified at , where . - If
then is inert at .1
Proof
First suppose
for . Then and on the other hand
contains both and . Thus by Bézout’s lemma we have , so .
Footnotes
-
2022. Algebraic number theory course notes, ¶2.12, pp. 38–39. ↩