Simple extension
A field extension
Classification
Let
Then
- If
is injective then is an infinite extension, whence is isomorphic to the field of rational functions ; - If
is not injective then is an extension of finite degree , and
where
Proof
By the First isomorphism theorem, the image of
is isomorphic to . Since is an integral domain, so is , and thus by Condition for a quotient commutative ring to be an integral domain, must be a prime ideal in . First, consider
, i.e. is injective. By the universal property for the Field of fractions, extends to a unique homomorphism where
is a field containing and , whence by definition . By injectivity, are linearly independent so we have an infinite extension. Now consider
. Since is a Euclidean domain and thus a PID, it follows for a unique monic irreducible nonconstant polynomial . Since is maximal in , the image of is a subfield containing , and by the same token as above we have , giving the claimed isomorphism.
Properties
- If
and have the same minimal polynomial , then there exists a unique isomorphism of field extensions such that . - More generally, an isomorphism of ground fields
such that lifts to an isomorphism of extensions .
Proof of 1–2
Note that an isomorphism of simple field extensions is completely determined by the image of the primitive element.
Now using the isomorphism described in Classification,
which necessarily fixes
and maps , proving ^P1, whereof ^P2 is a straightforward generalization.
Results
- Bound on the automorphism group of a finite simple extension.
- Simplicity of an algebraic extension
- By the Primitive element theorem, every finite separable extension is simple.
Footnotes
-
2009. Algebra: Chapter 0, §VII.1.2, pp. 387–388 ↩