Solvable Lie algebra
A Lie algebra
terminates in the zero subalgebra, lie
i.e.
Properties
- If
is solvable, then so too are all subalgebras and homomorphic images. - If
is a solvable ideal such that the quotient is solvable, then is solvable. - If
are solvable ideals, then so to is .
Proof of 1–3
Clearly if
, then for , so if the latter terminates so to does the former. Similarly given a epimorphism we have , and given proving ^P1 by induction.
Let
be the projection, and say . Then so . But then applying ^P1 the derived series of must terminate, and thus the derived series of terminates, proving ^P2. By the second isomorphism theorem we have the isomorphism
Since the latter is the homomorphic image of
, by ^P1 it is solvable, and thus is solvable by ^P2, proving ^P3.
See also
Footnotes
-
1972. Introduction to Lie Algebras and Representation Theory, §3,1, p. 10 ↩