Subalgebra generated by an algebraic element
Let
and is isomorphic to
Proof
Let
First we will show ^eq1. First note that the RHS is clearly a vector subspace, so it suffices to show that for all . Applying the division algorithm for polynomials where
. But so
. For the second statement, let
. It follows from above that to every there corresponds a unique with such that . Let be the map Now
is a ring isomorphism, since for any with an inverse by the evaluation map
.
Footnotes
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Stated without proof in 2008. Advanced Linear Algebra, §18, p. 259. ↩