Dixmierβs lemma
Let
Proof
By Schurβs lemma,
is a division algebra over π΄ π¬ π π½ ( π , π ) . Suppose π is transcendental over π β π΄ π¬ π π½ ( π , π ) , i.e. π iff π ( π ) = 0 for π = 0 . The division algebra generated by π ( π₯ ) β π [ π₯ ] is then π π ( π ) = { π ( π ) π ( π ) : π ( π₯ ) , π ( π₯ ) β π [ π₯ ] , π β 0 } = { π ( π ) : π ( π₯ ) β π ( π₯ ) } where
is the field of rational functions for π ( π₯ ) , and we have a straightforward isomorphism of division π -algebras π . By Lower bound on the dimension of the field of rational functions we have the inequality π ( π₯ ) β π ( π ) | π | β€ d i m π β‘ π ( π₯ ) = d i m π β‘ π ( π ) Since
is a vector space over π with scalar multiplication given by the action of π ( π ) , we have π d i m π β‘ π ( π ) β€ d i m π β‘ π and thus
| π | β€ d i m π β‘ π a contradiction.