Galois field
A Galois field is a field containing a finite number of elements. ring
The cardinality of a field is called its order,
and finite fields only exist for orders of the form
Construction and uniqueness
Let
Proof
Let
be the splitting field of πΉ over π₯ π β π₯ , and π π be the set of roots of πΈ β πΉ . Since the formal derivative π₯ π β π₯ , we have π β² ( π₯ ) = π π₯ π β 1 β 1 = β 1 , and thus g c d { π ( π₯ ) , π β² ( π₯ ) } = 1 is a separable polynomial of order π ( π₯ ) , so π . We show | πΈ | = π is a field, whence πΈ , since by definition πΈ = πΉ is generated by πΉ over πΈ . πΎ To this end, let
, whence π , π β πΈ and π π = π , so using the Freshmanβs dream π π = π ( π β π ) π β = π π + ( β 1 ) π π π = π π β π π = π β π . If
, π β 0 ( π π β 1 ) π = π π ( π π ) β 1 = π π β 1 proving
is closed under subtraction and division, thus it indeed a subfield by the Tests for subfields. πΈ For the converse, let
be a field such that πΉ . Then | πΉ | = π , so the multiplicative order of every element is a divisor of | πΉ Γ | = π β 1 . Therefore π β 1 π β 0 βΉ π π β 1 = 1 βΉ π π β π = 0 ; and we already have
. Thus, 0 π β 0 = 0 has π₯ π β π₯ roots in π , whence it is the splitting field, as stated. πΉ
Direct construction as quotient by a polynomial
A finite field of a given order can be constructed as a quotient of a polynomial ring. Given a polynomial ring
and an irreducible polynomial β€ π [ π₯ ] of degree π , then β is a field of order β€ π [ π₯ ] / β¨ π β© . ring π β
Properties
Let
is a perfect field, and consequently, irreducible polynomials inπΎ are separable.πΎ [ π₯ ]
Proof of 1
Since the Frobenius endomorphism is injective (Field homomorphisms are injective), by the Pigeonhole principle it must also be surjective, proving ^P1.
Other results
- Finite extension of a Galois field
- By Wedderburnβs little theorem these are the only finite division rings.
Footnotes
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2009. Algebra: Chapter 0, Β§VII.5.1, p. 441. β©