Separable polynomial
Let
Otherwise
Proof of equivalence
Suppose
is inseparable, i.e. it has a multiple root in a splitting field π ( π₯ ) β πΎ [ π₯ ] , i.e. πΉ π ( π₯ ) = ( π₯ β πΌ ) π π ( π₯ ) for some
, πΌ β πΉ , π ( π₯ ) β πΉ [ π₯ ] . It follows π β₯ 2 π β² ( π₯ ) = π ( π₯ β πΌ ) π β 1 π ( π₯ ) β ( π₯ β πΌ ) π π β² ( π₯ ) , so
is a common root of πΌ and π ( π₯ ) . Thus both are divisible by the minimal polynomial π β² ( π₯ ) of β ( π₯ ) β πΎ [ π₯ ] , so πΌ g c d πΎ [ π₯ ] { π ( π₯ ) , π π π₯ π ( π₯ ) } β 1 . For the converse, suppose
g c d πΎ [ π₯ ] { π ( π₯ ) , π π π₯ π ( π₯ ) } β 1 . so that in particular,
and π ( π₯ ) have a common root π β² ( π₯ ) in the algebraic closure. Write πΌ β ββ πΎ where π ( π₯ ) = ( π₯ β πΌ ) β ( π₯ ) and thus β ( π₯ ) β ββ πΎ ( π₯ ) π β² ( π₯ ) = β ( π₯ ) + ( π₯ β πΌ ) β β² ( π₯ ) whence
and thus ( π₯ β πΌ ) β£ β ( π₯ ) , so ( π₯ β πΌ ) 2 β£ π ( π₯ ) is inseparable. π ( π₯ )
See also Separable extension.
Properties
- If
is an inseparable ^irreducible, thenπ ( π₯ ) β πΎ [ π₯ ] .π β² ( π₯ ) = 0 - If [[Characteristic|
]], all irreducible polynomials are inseparable.c h a r β‘ πΎ = 0
Proof of 1
Since
is inseparable, π ( π₯ ) and π ( π₯ ) have a common irrreducible factor π β² ( π₯ ) , but since π ( π₯ ) is irreducible, π ( π₯ ) and π ( π₯ ) must be associate and thus of the same degree. But since π ( π₯ ) , it follows π ( π₯ ) β£ π β² ( π₯ ) , proving ^P1. ^P2 is an immediate corollary. π β² ( π₯ ) = 0
Footnotes
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2009. Algebra: Chapter 0, Β§VII.4.2, p. 434 β©