Ladder operator
Let
i.e.
Properties
- If
is a Hermitian operator andπ then either[ π , π ] = π π is real orπ ; andπ | π β© = 0 and thus[ π , π β ] = β π π β .π π β | π β© = ( π β π ) π β | π β© - A (pseudo)Vector operator
has raising and lowering operators forΛ π byΛ π π§ . proveΛ π Β± = Λ π π₯ Β± π Λ π π¦
Proof of 1
Let
be an eigenvector such that | π β© , where π | π β© = π | π β© is real by ^P2. Assuming π , then π | π β© β 0 is also an eigenvalue of π + π which must also be real. Now π [ π , π β ] = π π β β π β π = ( π π β π π ) β = [ π , π ] β = β [ π , π ] β = β π π β proving ^P1