Properly discontinuous group action
Orbit space of a properly discontinuous group action
Let
Proof
Let
. Since π₯ = π ( Λ π₯ ) = πΊ Λ π₯ β π acts properly discontinuously, πΊ has an open neighbourhood Λ π₯ such Λ π for any πΎ 1 Λ π β© πΎ 2 Λ π = β with πΎ 1 , πΎ 2 β πΊ . Then πΎ 1 β πΎ 2 is an evenly covered open neighbourhood of π = π ( Λ π ) = πΊ Λ π : π₯ and π β 1 ( π ) = π β 1 ( π ( Λ π ) ) = β¨Ώ πΎ β πΊ πΎ Λ π is a homeomorphism for each π βΎ πΎ Λ π : πΎ Λ π β π , since it is surjective and continuous (by construction), injective (no to points in πΎ β πΊ lie in the same orbit by proper continuity), and open (in fact Λ π is open, since π open implies Λ π open for all πΎ Λ π , so πΎ is open and thus β πΎ πΎ Λ π = π β 1 π is open). Thus every π = π ( Λ π ) has an evenly covered neighbourhood, so π₯ β π is a covering of the orbit space π with π itself. Λ π
Properties
- A stronger result is obtained for the Orbit space of a properly discontinuous effective group action:
is itself the deck transformation group.πΊ - If
is simply connectedΛ π andπ 1 ( π , π₯ 0 ) = πΊ is a Universal covering.π
Footnotes
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2010, Algebraische Topologie, pp. 81β82 β©