Projective module
An
This is equivalent to any of the following1
preserves epimorphisms;π π¬ π π½ ( π , β ) - Any Module epimorphism
splits;πΌ : π β π is a direct summand of a free module, i.e.π for some moduleπ β π β π ( πΌ ) and some cardinalπ ;πΌ is exact.π π¬ π π½ ( π , β )
Proof
If ^P1 holds, then taking
and π΅ = π gives ^P2. π = 1 π If ^P2 holds, consider an epimorphism
. Then the split short exact sequence π : π ( πΌ ) β π 0 β k e r β‘ π βͺ π ( πΌ ) β π β 0 guarantees the required direct sum decomposition, giving ^P3.
Note that
is already exact if π π¬ π π½ ( π , β ) , so since π = π π π¬ π π½ ( β π β πΌ π π , π ) β β π β πΌ π π¬ π π½ ( π π , π ) it follows from ^P1 that ^P3 implies ^P4.
Noting that being a module epimorphism is the same as being a regular epimorphism, and that the latter must be preserved by exact functors, it is clear that ^P4 implies ^P3.
Footnotes
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2011. Introduction to representation theory, Β§8.1, pp. 205β332 β©