Rolleβs theorem
Let
Proof
By the extreme value theorem
reaches either its maximum or minimum at π , for if both lay on the boundary then π β ( π , π ) would be constant. Without loss of generality assume π has a maximum at π (otherwise consider π ). Clearly β π π β² ( π + ) = l i m π β 0 + π ( π + π ) β π ( π ) β β [ β β , 0 ] and similarly
π β² ( π β ) = l i m π β 0 β π ( π + π ) β π ( π ) β β [ 0 , β ] as required.
In case