Specific heat of an ideal gas
The molar specific heat of an ideal gas at constant volume and constant pressure respectively are given by
where
Thermodynamic derivation
By ^Quasistatic we have
. At constant volume Δ π = π πΈ + π π π and thus π π = 0 , so the Energy of an ideal gas gives Δ π = π πΈ and thus Δ π = πΌ π π π π π π = Δ π π π π = πΌ π whence
Similarly at constant pressure πΈ = π π π π so applying the Ideal gas law and noting π π = 0 π π = 0 Δ π = π πΈ + π π π = π π π π π + π ( π π ) = π π π π π + π ( π π π ) = π ( π π + π ) π π wherefore
π π = Δ π π π π = π π + π as claimed.