The relationship between temperature and heat in a solid or liquid
In solids and liquids, which are not undergoing a phase change, the relation between heat in and Temperature change is
where
where
The values of
Explanation
By the First law of thermodynamics
Δ π = π πΈ + π π π so if
is constant, π . However if we keep Δ π = π πΈ constant, π so some heat gets spent as work. π π > 0
Note that at Phase change boundaries, it is impossible to increase temperature. See Heat of transformation.
Ideal gas
For an Ideal gas
Proof
For constant
, we have π . It follows πΈ = πΌ π π π . Hence for a quasistatic process ( π πΈ = πΌ π π π π ), it follows Δ π = π πΈ + π π π . Δ π = πΌ π π π π + π π π First we consider constant volume, whence
Δ π = πΌ π π π π = π πΈ βΉ πΆ π = 1 π Δ π π π = πΌ π hence
. πΈ = π πΆ π π Now consider constant pressure, whence
Δ π = π πΆ π π π + π ( π π ) = π πΆ π π π + π ( π π π ) = π πΆ π π π + π π π π = π ( πΆ π + π ) π π whence
. πΆ π = πΆ π + π