Centre of a group
The centre
Proof of normal subgroup
As shown above,
. Additionally, for any it is clear that since , so is closed under the binary operation. Since for any we can both pre- and postmultiply both sides to obtain for any , therefore , so is closed under the inverse. Hence is a subgroup of by Two step subgroup test. Now let and . Clearly . Hence is a Normal subgroup.
A related notion is the Centralizer in a group. The centre is the intersection of all centralisers.
Properties
- The centre is necessarily abelian.
Footnotes
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2017, Contemporary Abstract Algebra, pp. 67 ↩