Riemannian curvature
Let
and thus
where
Proof of equality and tensoriality
Let
be vector fields. Then and thus using the first equation
for any
, so indeed as claimed.
To show tensoriality it suffices to show that the map
is -linear. To this end let be a scalar field. Then and
Thus
where the final terms cancel since ^eq2.
Conflicting conventions
The convention used here is that used by Evgeny Buchbinder and (for the most part) Wikipedia. Wald’s General relativity defines the torsion-free case acting on a 1-form
so that meaning the action on a vector field
is meaning
.
Given local coördinates
Derivation
We have
as required.
Relation to parallel transport
The curvature of an (intrinsic) space can be thought of as the failure a vector to return to its initial value after parallel transport along a loop, explaining why the structure of an affine connexion is a prerequisite.
Properties
, i.e. .
For a torsion free connexion
Assume
- Bianchi Identity I.
.
Proof
See also the properties of the Levi-Civita connexion.
Computing curvature
Besides the above expression using the connexion coëfficients, see the Vielbein method for computing curvature.
See also
- The Riemannian curvature can be used to define two “weaker” notions of curvartures, the Ricci curvature and Scalar curvature.
Footnotes
-
Note that this expression requires a Holonomic frame. ↩