Sequential continuity
A function between topological spaces
All continuous maps are sequentially continuous.
In case
Proof for first-countable equivalence
Let
and be topological space, be a map, and be a point. Let , and be first-countable. First, assume
is continuous at . Let be a sequence in with , and . Then , and thus there exists such that for all , whence for all . Therefore , without invoking the First countability axiom. For the converse, assume
is sequentially continuous at . Let a countable nested open neighbourhood basis of . Assume is not continuous at , i.e. there exists such that for all . We can then construct a sequence such that for all , where clearly , but for all . whence , contradicting our requirement that be sequentially continuous. Therefore, is continuous at .
Another topological property that can be shown using sequences for metric spaces is Sequential closedness.