Annihilator
Let
If
Proof of ideal
If
then for any π β π A n n β‘ π we have π‘ β π π‘ π β π = π‘ β ( π β π ) = π‘ ( 0 ) = 0 so
. With the additional assumption that π‘ π β π A n n β‘ π is a submodule, we have π β€ π π π π‘ β π = π β ( π‘ β π ) β π β π = 0 so
as required. π π‘ β π A n n β‘ π