Central extension of an abelian group
Let
Then
and given a \Set-section
which is alternating
Properties
In what follows, if
is abelian iffΛ π΅ .π 0 ( π΅ , π΅ ) = 0 - Consider the radical of
π 0
Then
that is,
Proof
Note
, and Λ π΅ = π π΅ e πΆ , from which one easily verifies ^P1. [ π π΅ e πΆ , s π΅ e πΆ ] = [ π π΅ , π π΅ ] Assume
, so π π e π β Λ π . Then π β π . Given any π 0 ( π , π΄ ) = l n β‘ [ π π , π π΄ ] = 0 , π π e π β Λ π΄ π π e π π π e π = e π π π π π e π = e π π π π π e π = π π e π π π e π so
. Similarly, if π π e π β π ( Λ π΄ ) then π π β π ( Λ π΄ ) . Therefore π 0 ( π , π΄ ) = l n β‘ [ π π , π΄ ] = 0 , proving ^P2. Λ π = π ( Λ π΄ ) Finally, noting that
is a group monomorphism, e x p e π 0 ( π , π ) = [ π π , π π ] = π π π π π β 1 π π β 1 π = π π + π e π 0 ( π , π ) π β 1 π + π e β π 0 ( π , π ) = e π 0 ( π , π ) β π 0 ( π , π ) proving ^P3.
Special cases
- Cyclic central extension of a free abelian group
- 2 central extension of an elementary abelian 2-group (includes extraspecial 2-groups)
Footnotes
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1988. Vertex operator algebras and the Monster, Β§5.2, pp. 104ff. β©