Central extension of an abelian group
2 central extension of an elementary abelian 2-group
Let
where
which is a quadratic form independent of
Proof
Clearly equivalent extensions determine the same squaring map. Noting that
, it follows that π ( π 2 π ) = 2 π = 0 is well defined, and since for any π , π β β€ 2 l n β‘ ( π π e π π π e π ) = l n β‘ ( π 2 π e 2 π ) = l n β‘ ( π 2 π ) + 2 π = l n β‘ ( π 2 π ) so
is independent of the section chosen. Now let π . Then π π π π e π = π π + π π π ( π , π ) = π ( π + π ) β π ( π ) β π ( π ) = l n β‘ ( π 2 π + π ) β l n β‘ ( π 2 π ) β l n β‘ ( π 2 π ) = l n β‘ ( π π π π e π π π π π e π π β 2 π π β 2 π ) = l n β‘ ( π π π π π β 2 π π π π π π β 2 π ) = l n β‘ [ π π , π π ] = π 0 as claimed.
Let
be a quadratic form, π : πΈ β β€ 2 be a { π₯ π } π π = 1 -basis of β€ 2 , and define a unique bilinear map so that πΈ π 0 : πΈ Γ πΈ β β€ 2 ( π₯ , π₯ ) β¦ π ( π₯ ) ( π₯ π , π₯ π ) β¦ 0 π < π Then by the Correspondence between 2-cocycles and central extensions there is a central extension
1 β β€ + 2 βͺ Λ πΈ β πΈ β 1 with the 2-cocycle
and thus the squaring map π 0 . π Now for uniqueness, suppose
1 β β€ + 2 βͺ π΅ π β πΈ β 1 is a central extension with squaring map
. Then the associated bilinear map is the polar form π . Defining a \Set-section π π of π ( β ) so that π π ( β ) : π β π = 1 π π π₯ π = π β π = 1 π π π π₯ π it is easily shown that
is the corresponding 2-cocyle and so π 0 is equivalent. ( π΅ , π )
Properties
Automorphisms
Letting
it follows
where for
cf. the analogous result for free abelian groups.2
Furthermore, if
where the isomorphism is natural, giving the short exact sequences
Footnotes
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1988. Vertex operator algebras and the Monster, Β§5.3, pp. 108β110 β©
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1988. Vertex operator algebras and the Monster, ΒΆ5.4.5, p. 114 β©