Inner group automorphism
The inner group automorphism
Proof of normal subgroup
That
is a subgroup follows from the fact that it is the image of the homomorphism I n n β‘ ( πΊ ) . Let Μ β : πΊ β A u t β‘ ( πΊ ) and π β πΊ . Then for any π β A u t β‘ ( πΊ ) β β πΊ ( π Μ π π β 1 ) ( β ) = ( π Μ π ) ( π β 1 ( β ) ) = π ( π π β 1 ( β ) π β 1 ) = π ( π ) β π ( π ) β 1 = Μ π ( π ) ( β ) thus
. π Μ π π β 1 = Μ π ( π ) β I n n β‘ ( πΊ )
By the First isomorphism theorem, this is isomorphic to