Centre of a group
The centre
Proof of normal subgroup
As shown above,
. Additionally, for any π β π ( πΊ ) it is clear that π , π β π ( πΊ ) since π π β π ( πΊ ) , so π π π₯ = π π₯ π = π₯ π π is closed under the binary operation. Since π ( πΊ ) for any π π₯ = π₯ π we can both pre- and postmultiply both sides to obtain π₯ β πΊ for any π₯ π β 1 = π β 1 π₯ , therefore π₯ , so π β 1 β π ( πΊ ) is closed under the inverse. Hence π ( πΊ ) is a subgroup of π ( πΊ ) by Two step subgroup test. Now let πΊ and π β πΊ . Clearly β β π ( πΊ ) . Hence π β π β 1 = π π β 1 β = β β π ( πΊ ) is a Normal subgroup. π ( πΊ )
A related notion is the Centralizer in a group. The centre is the intersection of all centralisers.
Properties
- The centre is necessarily abelian.
Footnotes
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2017, Contemporary Abstract Algebra, pp. 67 β©