Commutator
Let
which together with the associative product of
Proof of Poisson algebra
Clearly for all
and π₯ , π¦ , π§ β π΄ π , π β π
[ π₯ , π π¦ + π π§ ] = π [ π₯ , π¦ ] + π [ π₯ , π§ ] [ π π₯ + π π¦ , π§ ] = π [ π₯ , π§ ] + π [ π¦ , π§ ] [ π₯ , π₯ ] = π₯ π₯ β π₯ π₯ = 0 hence the commutator is an alternating multilinear map. Now
0 = [ π₯ , [ π¦ , π§ ] ] + [ π¦ , [ π§ , π₯ ] + [ π§ , [ π₯ , π¦ ] ] = [ π₯ , π¦ π§ β π§ π¦ ] + [ π¦ , π§ π₯ β π₯ π§ ] + [ π§ , π₯ π¦ β π¦ π₯ ] = π₯ π¦ π§ β π₯ π§ π¦ β π¦ π§ π₯ + π§ π¦ π₯ + π¦ π§ π₯ β π¦ π₯ π§ β π§ π₯ π¦ + π₯ π§ π¦ + π§ π₯ π¦ β π§ π¦ π₯ β π₯ π¦ π§ + π¦ π₯ π§ hence the commutator is a Lie bracket. Finally
[ π₯ , π¦ π§ ] = π₯ π¦ π§ β π¦ π§ π₯ = π₯ π¦ π§ β π¦ π₯ π§ + π¦ π₯ π§ β π¦ π§ π₯ = [ π₯ , π¦ ] π§ + π¦ [ π₯ , π§ ] as required.
See also Anticommutator and Supercommutator.
Properties
(see above)[ π₯ , π¦ π§ ] = [ π₯ , π¦ ] π§ + π¦ [ π₯ , π§ ] π₯ π¦ = π¦ π₯ + [ π₯ , π¦ ] - Every Unital subalgebra is a Lie subalgebra under the commutator.
Graded structure
If the associative algebra